Question

I checked for forums but I found like this:

ofstream outfile;
outfile.open ("test.txt");
outfile.open ("\\data\\test.txt");

But I want to open a file in same level directory. How can I do this?

My C++ exe file is in release directory, I need to open a file in log directory.

root
-somefolder
--release
--test
--log

This didn’t worked:

outfile.open(".\\log\\test.txt",ios::app)

Answer 1

Try outfile.open("..\\log\\test.txt",ios::app)