Question

I checked the Search, but none seem to answer this Question.. I expect it to be farely simple though:
I have a query that results in two columns, but I need it to result in two rows.. Anyone know how?

this is the query:

               SELECT        (SELECT        COUNT(Id) AS Expr1
                      FROM            Table
                      WHERE        (Description LIKE 'door%')) AS Door,
                         (SELECT        COUNT(Id) AS Expr1
                           FROM            Table AS Table_1
                           WHERE        (Description LIKE 'window%')) AS Window

The result I GET is (of course):

[Door]     [Window]
56         34

The result I’d LIKE to have is the following:

[OPTION]    [NROfRecords]
Door        56
Window      34

Any Ideas? Thanks in advance!

Answer 1

SELECT 'Door'   AS Option, COUNT(id) FROM table WHERE description LIKE 'door%'
UNION ALL
SELECT 'Window' AS Option, COUNT(id) FROM table WHERE description LIKE 'window%'

OR…

WITH
  filtered AS
(
  SELECT
    CASE WHEN description LIKE 'door%'   THEN 'Door'
         WHEN description LIKE 'window%' THEN 'Window'
                                         ELSE 'Other' END AS option,
    *
  FROM
    yourTable
  WHERE
       description LIKE 'door%'
    OR description LIKE 'window%'
)
SELECT
  option,
  COUNT(id)
FROM
  filtered
GROUP BY
  option

Or…

SELECT
  lookup.option,
  COUNT(id)
FROM
(
  SELECT 'door'   AS option
  UNION ALL
  SELECT 'window' AS option
)
  AS lookup
INNER JOIN
  yourTable
    ON yourTable.description LIKE lookup.option + '%'
GROUP BY
  lookup.option