Question

I copied and pasted this example and filled in my own email addresses.

# Import smtplib for the actual sending function
import smtplib

# Import the email modules we'll need
from email.mime.text import MIMEText

# Open a plain text file for reading.  For this example, assume that
# the text file contains only ASCII characters.
fp = open('/Users/Jon/dev/iit/test-tools/logs/practice_tests.test_one.log', 'rb')
# Create a text/plain message
msg = MIMEText(fp.read())
fp.close()

me = '[e-mail]'
you = '[e-mail]'

# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = 'The contents of the log file'
msg['From'] = me
msg['To'] = you

# Send the message via our own SMTP server, but don't include the
# envelope header.
s = smtplib.SMTP('localhost', 1025)
s.sendmail(me, [you], msg.as_string())
s.quit()

I then opened another terminal window and ran the following command:

python -m smtpd -n -c DebuggingServer localhost:1025

When I run the file to send email, it finishes without error, and the terminal that is running the python -m smtpd -n -c DebuggingServer localhost:1025 command prints a nice log message that looks correct:

---------- MESSAGE FOLLOWS ----------
Content-Type: text/plain; charset="us-ascii"
MIME-Version: 1.0
Content-Transfer-Encoding: 7bit
Subject: The contents of the log file
From: [e-mail]
To: [e-mail]
X-Peer: 127.0.0.1

line one
line two
line three
------------ END MESSAGE ------------

But when I check my yahoo email address, the email never arrives. I have waited about 5 minutes, which I think is adequate. What did I do wrong?

Answer 1

From the smtpd documentation

class smtpd.DebuggingServer(localaddr, remoteaddr)
Create a new debugging server. Arguments are as per SMTPServer. Messages will be discarded, and printed on stdout.