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Home/ Questions/Q 8742651
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:32:15+00:00 2026-06-13T11:32:15+00:00

I could get a set of ICompilationUnit using the following code, but I need

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I could get a set of ICompilationUnit using the following code, but I need get the physical file path from the ICompilationUnit or IWorkspaceRoot.

How can I do that?

private static Set<ICompilationUnit> getFiles(String projname)   
throws CoreException {
    IWorkspaceRoot ws = ResourcesPlugin.getWorkspace().getRoot();
    IProject proj = ws.getProject(projname);
    IJavaProject javaProject = JavaCore.create(proj);
    Set<ICompilationUnit> files = new HashSet<ICompilationUnit>();
    javaProject.open(new NullProgressMonitor());
    for (IPackageFragment packFrag : javaProject.getPackageFragments()) {
        for (ICompilationUnit icu : packFrag.getCompilationUnits()) {
            files.add(icu);
        }
    }
    javaProject.close();
    return files;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:32:16+00:00Added an answer on June 13, 2026 at 11:32 am

    Send the ICompilationUnit the getUnderlyingResource() method. It returns an IResource that can tell you if it’s a file and, if so, what the various forms of its file name and path are.

    Note that a null can be returned, too, so watch for that.

    something like this:

       // resource is an IResource returned by sending 
       // an iCompilationUnit the getUnderlyingResource() method
    
    if (resource.getType() == IResource.FILE) {
    
        IFile ifile = (IFile) resource;
    
        String path = ifile.getRawLocation().toString();
    
    }
    
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