Question

I could not understand how the below program code outputs that value.Please help me to understand.

#include<stdio.h>
char*s="char*s=%c%s%c;main(){printf(s,34,s,34);}";
int main()
{
        printf(s,34,s,34);
        return 0;
}

output:

char*s="char*s=%c%s%c;main(){printf(s,34,s,34);}";main(){printf(s,34,s,34);}

Answer 1

Your printf statement is effectively equivalent to:

printf("char*s=%c%s%c;main(){printf(s,34,s,34);}", 34, s, 34);
               ^ ^ ^

I’ve marked the conversion specifiers with ^. These get replaced with, respectively:

• " – the ASCII character corresponding to 34
• the contents of *s
• " – the ASCII character corresponding to 34