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Home/ Questions/Q 7646427
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T10:12:20+00:00 2026-05-31T10:12:20+00:00

I create a xml document in jQuery as following var xmlDocument = $(‘<xml/>’); var

  • 0

I create a xml document in jQuery as following

var xmlDocument = $('<xml/>');
var foo = $('<foo/>');
var bar = $('<bar/>');

foo.append(bar);
xmlDocument.append(foo);

and try to forwards it to the server.

$.ajax({
   url             :   'js/foobar.php',
   type            :   'POST',
   precessData     :   false,
   contentType     :   'text/xml',
   data            :   xmlDocument,
   sucess          :   function( data ) {
      alert('success');
   },
   error           :   function() {
      alert('failed to send ajax request');
   },
   complete        :   function() {
      alert('ajax request completed');
   }
});

Even if the server echos a ‘foo’ only, I get the alert('ajax request completed') and not the alert('success'). What am I doing wrong? Is it the way I’m creating the xml document or is it the way I forward it to the server?

An ajax request without a xml document works fine and I get the ‘foo’ back.

UPDATE #1

After changing precessData to processData and sucess to success i get the failed to send ajax request dialog.

When I change the data parameter in the ajax method to

$.ajax({
   ...
   data :   {
      data: xmlDocument
   },
   ...
});

I also get the failed to send ajax request dialog.

The code on the server side should be fine cause it’s only

<?php
echo 'foo';
?>

UPDATE #2

I converted my string as in AndreasAL’s answer

// Convert to string instead of DOM Elements
xmlDocument = $("<wrap/>").append(xmlDocument).html();

// Url encode the string
xmlDocument = encodeURIComponent(xmlDocument);

but i still get the same dialog box (failed to send the ajax request). So i thought the error could be in my xml document and overwrote my xml document by using the code snipplet from AndreasAL’s answer.

xmlDocument = $('<xml/>');
foo = $('<foo/>').appendTo(xmlDocument);
bar = $('<bar/>').appendTo(foo);

Still the same behaviour.

So I checked my xml document again and printed it in a dialog box and it looks fine.

I’m running out of ideas where the error could be …

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:12:22+00:00Added an answer on May 31, 2026 at 10:12 am

    Finally, I decided to convert the xml document and send it as a string to the server.

    $xmlString = $(xmlDocument).html();
    

    Due to the fact, that I only have to store the recieved data, it makes no difference if I’m revieving it as string or xml.

    I only had to change my ajax request at everything works fine now.

    $.ajax({
       url             :   'js/foobar.php',
       type            :   'POST',
       data            :   'data=' + xmlString,
       success         :   function( data ) {
          alert(data);
       },
       error           :   function() {
          alert('failed to send ajax request');
       },
       complete        :   function() {
          alert('ajax request completed');
       }
    });
    
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