Question

i created a form mainwindow class in QT creator, and an action element in a menuBar, and i want that when we click on it, it show an other form called DataWindow

Here is my mainwindow.h

private slots:
    void on_actionNouvellesDonnees_clicked();

Here is my mainwindow.ccp

void MainWindow::on_actionNouvellesDonnees_clicked() {
    DataWindow w;
    w.show();
}

But when i debug and i click on my action menu, the DataWindow is not showed… and the debug tool said me :

QMetaObject::connectSlotsByName: No matching signal for on_actionNouvellesDonnees_clicked()

Thanks for any help !

Complete mainwindow.ccp :

#include <QtGui/QApplication>
#include <QApplication>
#include <QMessageBox>

#include "mainwindow.h"
#include "ui_mainwindow.h"
#include "datawindow.h"

MainWindow::MainWindow(QWidget *parent) :
    QMainWindow(parent),
    ui(new Ui::MainWindow)
{
    ui->setupUi(this);
    //QObject::connect(ui->actionNouvellesDonnees, SIGNAL(triggered()), this, SLOT(on_actionNouvellesDonnees_clicked()));
}

MainWindow::~MainWindow()
{
    delete ui;
}
void MainWindow::on_actionNouvellesDonnees_triggered() {

    DataWindow w;
    w.show();
}

Complete mainwindow.h

#ifndef MAINWINDOW_H
#define MAINWINDOW_H

#include <QMainWindow>

namespace Ui {
class MainWindow;
}

class MainWindow : public QMainWindow
{
    Q_OBJECT

public:
    explicit MainWindow(QWidget *parent = 0);
    ~MainWindow();

private slots:
    void on_actionNouvellesDonnees_triggered();

private:
    Ui::MainWindow *ui;
};

#endif // MAINWINDOW_H

Answer 1

Which signal do you connect on_actionNouvellesDonnees_clicked? If it is an action(like in main menu) correct signal isn’t “clicked()”, you can use “triggered()”.

Try this

QObject::connect(ui->actionNouvellesDonnees, SIGNAL(triggered()), this, SLOT(on_actionNouvellesDonnees_clicked()));