Question

I created a java phonebook (desktop app) , on my pc there’s a program that outputs the number of the caller. it’s an 8 digits number.

here’s how it works

I want to crawl only 8 digits numbers from the popup, so lets say this is a popup:

    My name is someone like you, i am 22 years old, i was born in 19/10/1989,
    my phone number is 34544512
    my brother is someone like me he is 18 years old, born in 9101993 
    his number is 07777666

in this example, i want to crawl 07777666 and 34544512 only.

I want to check the popup window every 2s for new numbers, if a caller calls me twice, his number will be already stored my db and if not I’ll store

Note: if that’s can’t be done, then forget about the popup, lets say it’s just a text being updated every 2 seconds, how to crawl it

This not a homework lol 😀

Answer 1

Use Java regular expressions. Create a regex of 8 or more digits and use it. You will be able to extract these 2 phone numbers from your text sample.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
    public static void main(String args[]) throws Exception {
        String testString = "My name is someone like you, i am 22 years old, i was born in 19/10/1989,"
                          + " my phone number is  34544512 3454451266"
                          + " my brother is someone like me he is 18 years old, born in 9101993 "
                          + " his number is 07777666";

        String[] pieces = testString.split("\\s+");
        String expression = "\\d{8,}";
        Pattern pattern = Pattern.compile(expression);
        for (int i = 0; i < pieces.length; i++) {
            if (pattern.matches(expression, pieces[i]))
                System.out.println(pieces[i]);
        }
    }
}