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Home/ Questions/Q 942669
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:18:40+00:00 2026-05-15T22:18:40+00:00

I created a lambda expression inside my std::for_each call. In it there is code

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I created a lambda expression inside my std::for_each call.

In it there is code like this one, but I have building error telling me that

error: expected primary-expression before ‘return’
error: expected `]' before ‘return’

In my head I think that boost-lambda works mainly with functors, so since return statement it isn’t like that, calling it doesn’t work.

Do you know what it is and how to fix it?

Thanks
AFG

namespace bl = boost::lambda;
int a, b;
bl::var_type::type a_( bl::var( a ) );
bl::var_type::type b_( bl::var( b ) );

std::for_each( v.begin(), v.end(), (
// ..do stuff here
if_(  a_ > _b_ )
[
std::cout << _1,
 return
]
));
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  1. Editorial Team
    Editorial Team
    2026-05-15T22:18:40+00:00Added an answer on May 15, 2026 at 10:18 pm

    You cannot use return instruction inside lambda expression. Use constructions like if_then_else_return. They offer syntax that allows producing results.
    But in your case return is not even required, just throw it away.

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