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Home/ Questions/Q 7217841
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T21:24:17+00:00 2026-05-28T21:24:17+00:00

I created a simple templating/content parser where you can specify where blocks of text

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I created a simple templating/content parser where you can specify where blocks of text should be placed in the final output page. The “markup” I settled on is something like @blockname> on it’s own line. So to put a block of text in the body, you would start the text with @body>. The blockname can be anything you want to use, but it can’t contain spaces or line breaks.

Everything works fine, except if there is a text string like @body> embedded in the text. It splits on the embedded text too. This seems really simple, I just want to match a line that starts with @ followed by any non-white space characters and ending with > at the end of the line. The command I have right now that almost works is:

preg_split('/@([^\s].*?[^>])>/', $tpl, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);

It seems I should just be able to use ^@([^\s].*?[^>])>$, but that doesn’t work at all. I feel I’m missing something simple. I’ve tried a bunch of modifiers at the end to no avail.

Example text to parse:

@css>
.example {font-weight:bold;}

@js>
function example() {
    alert('example');
}

@body>
This is some sample @body> text to show

That ideally the regex split would come back with:

Array
(
[0] => css
[1] => 
.example {font-weight:bold;}
[2] => js
[3] => 
function example() {
alert('example');
}
[4] => body
[5] => 
This is some sample @body> text to show
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T21:24:17+00:00Added an answer on May 28, 2026 at 9:24 pm

    I just want to match a line that starts with @ followed by any
    non-white space characters and ending with > at the end of the line.

    You can do that with:

    "/^@(\\S+)>$/m"
    

    With PHP quoting. You were probably missing the /m switch which makes ^/$ match beginning/end of lines, and not only strings.

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