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Asked: 2026-06-06T06:09:34+00:00

I created dynamic web project , and add 2 items : index.jsp page like

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I created dynamic web project , and add 2 items :

  1. index.jsp page like this :

    <%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
        <form action="GrettingServlet" method="POST">
        First Name: <input type="text" name="firstName" size="20"><br>
        Last Name: <input type="text" name="lastName" size="20">
        <br><br>
        <input type="submit" value="Submit">
</form> 

</body>
</html>

  2. in default package servlet like this (called GrettingServlet.java):

    import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class GrettingServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

    public GrettingServlet() {
        super();
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
    }

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        response.setContentType("text/html;charset=UTF-8");
        PrintWriter out = response.getWriter();
        String firstName = request.getParameter("firstName").toString();
        String lastName = request.getParameter("lastName").toString();

        out.println("<html>");
        out.println("<head>");
        out.println("<title>Servlet GreetingServlet</title>");
        out.println("</head>");
        out.println("<body>");
        out.println("<p>Welcome " + firstName + " " + lastName + "</p>");
        out.println("</body>");
        out.println("</html>");

        out.close();
    }

}

I installed tomcat6 so that I have Apache Software Foundation folder .
finally I want to create war file of this project, so I chose on the project Export>War file and in the Destination text I chose the webapps folder in the path C:\Program Files (x86)\Apache Software Foundation\Tomcat 6.0\webapps .
the project called MyFirstServlet . and in order to see the form of index.jsp on the server i write in the browser http://localhost:8080/MyFirstServlet/ but I get the message 

HTTP Status 404 - /MyFirstServlet/

type Status report

message /MyFirstServlet/

description The requested resource (/MyFirstServlet/) is not available.

Apache Tomcat/6.0.35

the servlet mapping is this :

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>MyFirstServlet</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <description>new</description>
    <display-name>GrettingServlet</display-name>
    <servlet-name>GrettingServlet</servlet-name>
    <servlet-class>GrettingServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>GrettingServlet</servlet-name>
    <url-pattern>/GrettingServlet</url-pattern>
  </servlet-mapping>
</web-app>

I checked the tomcat and it on service status : started

What can be the problem ?

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1 Answer

  1. Editorial Team

    From the given example, you are expected to deploy your web application into your Tomcat as MyFirstServlet.war (or as an exploded directory – this makes no difference) and have your GrettingServlet mapped to the application root – if you want the servlet to handle the root:

    Your /WEB-INF/web.xml should have these so:

    <servlet>
    <servlet-name>GrettingServlet</servlet-name>
    <servlet-class>your.package.GrettingServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>GrettingServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

    Note the typo: “Gretting” (in servlet and mappings) vs “Greeting” (in JSP form)

    With your setup you should be pointing your browser at http://localhost:8080/MyFirstServlet/GrettingServlet to reach the servlet.

    If your idea is to have JSP page to handle the root, then you should browse to either http://localhost:8080/MyFirstServlet/<yourJSPName>.jsp or have the JSP called index.jsp or default.jsp (see <welcome-file-list/> section of your web.xml). In this case your idea, I guess, is to display a JSP and then post to the servlet, therefore make sure your servlet specification and mapping is correct (web.xml servlet mapping and the JSP form action attribute).

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