Question

I currently have a dropdown box which enters an integer into a table. It’s adding $myVariable choice to a list in the database based on the ID singularly.

What i’m struggling to do is convert this dropdown selection system to a checkbox system where the user checks which $myVariable’s and inserts them into a database.

How can I insert multiple ID’s [myVariableID] into a database in one insert statement?

Edit:
I have a table with a list of X. The X has an ID, so I want to insert that ID into another table.

X 1 has ID 1

X 2 has ID 2

Inserting these values into a table allows me to see what X have been associated using a linking table.

Therefore, with a list of checkboxes (Outputs all of X that has been added), I need to insert the ID of X multiple times into the linking table.

It is currently limited because the dropdown selects X, and X ID. If I use checkboxes, how do I dynamically grab the ID of X, and insert whatever X‘s are selected, and add X ID multiple based on the checkbox selections.

Example

Name      ID
X1    ||  1
X2    ||  2
X3    ||  3
X4    ||  4

User selects X1, X2, insert ID 1, 2 into a database table. I can’t have $var1, $var2, .. etc because the list might be added to. This is why I thought of an array or foreach

Problem:
A dropdown selection has one value ($variable)
A checkbox system (What I want) has multiple possible values.

Answer 1

INSERT supports inserting multiple values.

Quick example:

INSERT INTO table (id, something) VALUES (1, 10), (2, 11), (1, 28)