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Home/ Questions/Q 634973
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:21:15+00:00 2026-05-13T20:21:15+00:00

I currently have a form that submits through ajax and when it’s successful it

  • 0

I currently have a form that submits through ajax and when it’s successful it puts the information at the top of a list.

My current layout is

<div id="projects">
    <div class="project">
         ....
    </div>
    <div class="project">
         ....
    </div>
    ....   
</div>

And I do the inserting by

var project = $('<div class="project">' +
                      '<div class="name">'+data.title+'</div>' +
                      '<div class="desc">'+data.desc+'</div>' +
                 '</div><hr />').fadeIn(1000, function() { }
                                   );
 $('.project:first-child').before(project);
 $('.project:first-child').highlightFade({color:'#e3e373',speed:4000,iterator:'exponential'});

This works fine once there’s something in the list, but when there is nothing there it fails (because it can’t find a class with project.

How would I go about improving this so it’ll work even if there are no projects in the list?

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:21:15+00:00Added an answer on May 13, 2026 at 8:21 pm

    I would do it slightly differently.

    First, I would avoid constructing markup that way, at least in parts. If data.title contains, say, < then it won’t be escaped properly. It’s better to use text() for that.

    Second, it’s faster to create DOM elements rather than insert raw markup. In this case $("<div>") is equivalent to $(document.createElement("div")).

    Third, use prependTo to insert the content. Then you have no issues.

    So:

    $("<div>").addClass("project")
      .appendChild($("<div>").addClass("name").text(data.title))
      .appendChild($("<div>").addClass("desc").text(data.desc));
      .hide().prependTo("#projects").fadeIn(1000);
    
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