Question

I currently have a pattern substitution that does the following:

x = re.sub('(\d+)','\g<1>','100')
=> x = 100

I need to be able to divide the integer by 10 in the substitution as the pattern and substitution are inputs from database text fields (so I can’t use code). Is there a way to do this so that => x = 10

Thanks,
Richard

Answer 1

import re

t = 'a b c 100 200'

f = lambda x: str(int(x.group(0)) / 10)
re.sub('\d+', f, t)

# returns 'a b c 10 20'