Question

I currently have a templated class, with a templated method. Works great with functors, but having trouble compiling for functions.

Foo.h

template <typename T>
class Foo {
   public:
   // Constructor, destructor, etc...
   template <typename Func>
   void bar(T x, Func f);
};

template <typename T>
template <typename Func>
void Foo<T>::bar(T x, Func f) { /* some code here */ }

Main.cpp

#include "Foo.h"
template <typename T>
class Functor {
    public:
    Functor() {}
    void operator()(T x) { /* ... */ }
    private:
    /* some attributes here */
};

template <typename T>
void Function(T x) { /* ... */ } 

int main() {
   Foo<int> foo;
   Functor<int> F;
   foo.bar(2, F); // No problem
   foo.bar(2, Function); // <unresolved overloaded function type>
   return 0;
}

Answer 1

If you want to get a function pointer for an overloaded function, you need to tell the system which function out of the overload set you want:

foo.bar(2, static_cast<void(*)(int)>(&Function);

In the quoted case the function is actually a template, i.e., you can also refer to its specialization directly:

foo.bar(2, &Function<int>);