Home/ Questions/Q 8181237
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-06-07T00:27:09+00:00

I currently have a XSLT 2.0 Stylesheet that I am trying to remove empty

  • 0

I currently have a XSLT 2.0 Stylesheet that I am trying to remove empty P Tags from the output. I have tried the following RegEx with no success:

replace($string,"<p>[\s{2,}]*</p>","")

The output from the Stylesheet at the moment looks like below:

<p>Some Text!</p>
<p></p>
<p>Some Text!</p>
<p> </p>
<p>  </p>
<p>Some Text!</p>

From this I want the output to strip the P tags that have just 1 or more spaces within them, so it would look like this:

<p>Some Text!</p>
<p>Some Text!</p>
<p>Some Text!</p>

Thanks

🙂

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    I would suggest using next regular expression: /<p>(|\s+)<\/p>/

    Explanation:

    <p>       # Match <p>
(         # Try to match...
  |\s+    #   nothing or the space character any number of times
)         # ...match end
<\/p>     # Match </p>

    You can see it in action by the link http://regexr.com?31f6a (be sure to switch to ‘Replace’ mode and set replacement text to nothing).

    Update

    Actually, the (|\s) expression and \s* does the same thing (Thanks to Rawling), so you can write the main expression as /<p>\s*<\/p>/.

    • 0