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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:29:40+00:00 2026-05-13T18:29:40+00:00

I currently have the following code to parse a csv file using the standard

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I currently have the following code to parse a csv file using the standard csv library

@parsed_file=CSV::Reader.parse(params[:dump][:file])
@parsed_file.each  do |row|
#some code
end

I want to move this to faster csv for the increased speed. Does anyone know the equivalent of the above for FasterCSV?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:29:41+00:00Added an answer on May 13, 2026 at 6:29 pm
    CSV::Reader.parse(File.open('file.csv')){|row| puts row} 
    or
    CSV::Reader.parse("some, content\nanother, content"){|row| puts row} 
    

    and

    FasterCSV.parse(File.open('file.csv')){|row| puts row}
    or
    FasterCSV.parse("some, content\nanother, content"){|row| puts row}
    

    are equivalent.

    But

    FasterCSV.read('filename') 
    

    takes filename as parameter and reads and parse data from the file however you are dumping the file content as you are passing data in the parameter

    @parsed_file = FasterCSV.parse(params[:dump][:file])
    @parsed_file.each do |row| 
      puts row
      # and do some operations
    end
    

    should work fine.

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