Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8673029
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T19:21:07+00:00 2026-06-12T19:21:07+00:00

I currently have the regex ‘([^: ]+):([^ ]+)?’ , which when given a string

  • 0

I currently have the regex '([^: ]+):([^ ]+)?', which when given a string like This is a correct:test msg: a b c bool:y returns [('correct', 'test'), ('msg', ''), ('bool', 'y')] (using pythons re.findall).

I actually want it to return something like [('correct', 'test'), ('msg', 'a b c'), ('bool', 'y')]. How do I force regex to look inside the second chunk, and see if theres a : in it?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T19:21:09+00:00Added an answer on June 12, 2026 at 7:21 pm

    You can use a positive lookahead on the second part, e.g.

    '([^ :]+): *(.+?)?(?:(?= [^ ]+:)|$)'
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have string which rich text content something like this for example <p>Hello</p> <br/>
I need to alter a RegEx pattern. I currently have this which matches all
Hey guys i have the string: /new/krymson/ currently i have the regex: /\/new\// which
Currently I have this regex: [\d\.]+ I'm testing it with Regex Hero. You can
I currently have a regex pattern that matches a specific word, which includes arbitrary
I currently have this regex: $text = preg_replace(#<sup>(?:(?!</?sup).)*$key(?:(?!</?sup).)*<\/sup>#is, '<sup>'.$val.'</sup>', $text); The objective of the
Here is the regex I currently have (which kind of works): $regex = '/[\w
I currently have the regex: (?:(?:CD)|(?:DISC)|(?:DISK)|(?:PART))([0-9]+) currently this will match CD1, DISK2 etc I
Hello All , Thanks to @FailedDev I currently have the regex below which is
I currently have a coldfusion regex that checks whether a string is alphanumeric or

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.