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Home/ Questions/Q 6073217
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:14:49+00:00 2026-05-23T10:14:49+00:00

I currently have this code. function outputCalendarByDateRange($client, $startDate=2011-06-22, $endDate=’2011-06-26′) I want $startDate and $endDate

  • 0

I currently have this code.

function outputCalendarByDateRange($client, $startDate="2011-06-22", 
                               $endDate='2011-06-26') 

I want $startDate and $endDate to reflect today’s date and the date three days from now with it automatically updating. I’ve tried using

$startDate=date("Y-m-D")
$endDate=strtotime(date("Y-m-d", strtotime($todayDate)) . " +3 days");

and

$date1=date("Y-m-D")
$date2=strtotime(date("Y-m-d", strtotime($todayDate)) . " +3 days");
    function outputCalendarByDateRange($client, $startDate=$date1, 
                               $endDate=$date2)

none of these work. How do I make it work?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:14:50+00:00Added an answer on May 23, 2026 at 10:14 am

    you can’t use a statement in a function declaration, but you can set the value to null and check it at runtime:

    function foo( $bar = null )
    {
      if (is_null($bar))
      {
        $bar = 'baz';
      }
      ...code...
    }
    
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