Question

I currently have this code (thanks for the help from here). I need to create the first ProcessMessage as a thread and run the second ProcessMessage synchronously (on the current thread), then perform the Join on the single thread. Otherwise, I’ll have three threads doing effectively two things. How do I modify this to accomplish it? I am on .NET 3.5

Thread thRegion1 = new Thread(() =>
{
    if (Region1.Trim().Length > 0)
    {
        returnMessage = ProcessTheMessage(string.Format(queueName, Region1));
        Logger.Log(returnMessage);
    }
});

Thread thRegion2 = new Thread(() =>
 {
     if (Region2.Trim().Length > 0)
     {
         returnMessage = ProcessTheMessage(string.Format(queueName, Region2));
         Logger.Log(returnMessage);
     }
 });

thRegion1.Start();
thRegion2.Start();

thRegion1.Join();
thRegion2.Join();

Answer 1

You can do it like this:

Thread thRegion1 = new Thread(() =>
        {
            if (shawRegion1.Trim().Length > 0)
            {
                returnMessage = ProcessMessage(string.Format(queueName, 
                                                             shawRegion1));
                Logger.Log(returnMessage);
            }
        });

thRegion1.Start();

if (shawRegion2.Trim().Length > 0)
{
    returnMessage = ProcessMessage(string.Format(queueName, shawRegion2));
    Logger.Log(returnMessage);
}

thRegion1.Join();

This starts the thRegion1 thread and performs the other part of the work in the current thread. After that work is finished, it calls Join on thRegion1 which will return immediately, if thRegion1 is already finished with its work.