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Home/ Questions/Q 7700099
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T22:37:45+00:00 2026-05-31T22:37:45+00:00

I currently have this method: -(void)seperateGuides { DLog(GetGuideListCount: %i, [[appDelegate getGuideList] count]); columnOneArray =

  • 0

I currently have this method:

-(void)seperateGuides
{
   DLog("GetGuideListCount: %i", [[appDelegate getGuideList] count]);

   columnOneArray = [[NSMutableArray alloc] init];
   columnTwoArray = [[NSMutableArray alloc] init];
   columnThreeArray = [[NSMutableArray alloc] init];

   for (int i = 0; i < [[appDelegate getGuideList] count]; i = i + 3) {
      [columnOneArray addObject:[[appDelegate getGuideList]objectAtIndex:i]];
   }

   for (int i = 1; i < [[appDelegate getGuideList] count]; i = i + 3) {
      [columnTwoArray addObject:[[appDelegate getGuideList]objectAtIndex:i]];
   }

   for (int i = 2; i < [[appDelegate getGuideList] count]; i = i + 3) {
      [columnThreeArray addObject:[[appDelegate getGuideList]objectAtIndex:i]];
   }
}

And need to do this more dynamic, so I can define how many arrays I want and then get the arrays.

Different possibilities I’m considering is making it a mutli-dimensional array (although I’m not sure how to handle it in Objectvie-C), or making a method that simply loops through as many times as I define, the problem there is that I’m not quite sure how to get the different arrays.

A simple algorithm or another possible solution would be greatly appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T22:37:46+00:00Added an answer on May 31, 2026 at 10:37 pm

    The algorithm you’re describing sounds equivalent to what we do when we deal a deck of cards into multiple hands, so I’d do it like this:

    - (NSArray *)dealObjects:(NSArray *)objects intoArrays:(NSInteger)numArrays
    {
        NSMutableArray *arrays = [NSMutableArray arrayWithCapacity:numArrays];
        for (a = 0; a < numArrays; a++) {
            [arrays addObject:[NSMutableArray arrayWithCapacity:[objects count] / numArrays];
        }
        for (i = 0; i < [objects count]; i++) {
            [[arrays objectAtIndex:i % numArrays] addObject:[objects objectAtIndex:i]];
        }
        return arrays;
    }
    
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