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Home/ Questions/Q 8730605
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:03:30+00:00 2026-06-13T09:03:30+00:00

I currently lag panel data using data.table in the following manner: require(data.table) x <-

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I currently lag panel data using data.table in the following manner:

require(data.table)
x <- data.table(id=1:10, t=rep(1:10, each=10), v=1:100)
setkey(x, id, t) #so that things are in increasing order
x[,lag_v:=c(NA, v[1:(length(v)-1)]),by=id]

I am wondering if there is a better way to do this? I had found something online about cross-join, which makes sense. However, a cross-join would generate a fairly large data.table for a large dataset so I am hesitant to use it.

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:03:30+00:00Added an answer on June 13, 2026 at 9:03 am

    I’m not sure this is that much different from your approach, but you can use the fact that x is keyed by id

    x[J(1:10), lag_v := c(NA,head(v, -1)) ]
    

    I have not tested whether this is faster than by, especially if it is already keyed.

    Or, using the fact that t (don’t use functions as variable names!) is the time id

    x <- data.table(id=1:10, t=rep(1:10, each=10), v=1:100)
    setkey(x, t)
    replacing <- J(setdiff(x[, unique(t)],1))
    x[replacing, lag_v := x[replacing, v][,v]]
    

    but again, using a double join here seems inefficient

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