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Home/ Questions/Q 877981
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:41:51+00:00 2026-05-15T11:41:51+00:00

I decided to learn LISP today, and have been playing around with it for

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I decided to learn LISP today, and have been playing around with it for a bit. I wrote a simple baby function just to test my understanding, and now understand that my understanding doesn’t understand as much as I had understood it to understand. 😀

Anyway, here is the function. The idea is that when it is called, e.g. (esexp base x) it should return the value base^x. So (esexp 3 4) = 3^4 = 81.

(I am using the CMU implementation of Common Lisp, if that matters.)

(defun esexp (base x)
  (if (= x 0)
      1
      (if (< x 0)
          (/ esexp (base (+ x 1)) base)
          (* esexp (base (+ x 1)) base))))

This doesn’t work. I get errors that look like (Warning: This variable is undefined: SLBEXP) and (Error in KERNEL::UNBOUND-SYMBOL-ERROR-HANDLER: the variable SLBEXP is unbound.) So. What am I doing wrong? AND would there be a better (or more LISP-ish way) to write this function?

ETA

Corrected code:

(defun esexp (base x)
  (if (= x 0)
      1
      (if (< x 0)
          (/ (esexp base (+ x 1)) base) 
          (* (esexp base (- x 1)) base))))
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  1. Editorial Team
    Editorial Team
    2026-05-15T11:41:52+00:00Added an answer on May 15, 2026 at 11:41 am

    esexp(base (+ x 1))

    should be

    (esexp base (+ x 1))

    esexp is a function just like +. The syntax for invoking a function is

    (function-name arg1 arg2 ...)
    
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