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Home/ Questions/Q 8104177
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T23:45:33+00:00 2026-06-05T23:45:33+00:00

I declared a multidimensional array in C, like so: int arr[4][2]; int length =

  • 0

I declared a multidimensional array in C, like so:

int arr[4][2];
int length = 0;

But I can apparently add as many elements as I want:

void addStuff(){
    arr[length][0] = someVal;
    arr[length++][1] = someVal;
}

and it doesn’t give any errors. Does this mean I’m corrupting my memory somewhere in no-man’s land? Or is this some feature of C I don’t know about?

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  1. Editorial Team
    Editorial Team
    2026-06-05T23:45:34+00:00Added an answer on June 5, 2026 at 11:45 pm

    If you assign past the array size, you’re definitely corrupting memory somewhere – the program may segfault, or other data may get corrupted, or it may (by accident) behave correctly. There’s no bounds checking by default in C.

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