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Home/ Questions/Q 7570643
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T15:28:43+00:00 2026-05-30T15:28:43+00:00

I define a linked list in the same way as it is commonly used,

  • 0

I define a linked list in the same way as it is commonly used, i.e. with a data part and a

self referencing pointer. My logic of insertion is as follows:

struct node
{
    int data; //or any type.
    struct node *nextPtr;
}*start = NULL;
//main
struct *newPtr = (struct node *)malloc(sizeof(struct node *));
scanf("%d", newPtr->data); //or cout
newPtr->nextPtr = NULL;
if(start == NULL)
    start = newPtr;
else
{
    while(tempPtr->nextPtr != NULL)
    {
        tempPtr = tempPtr->nextPtr;
    }
    tempPtr->nextPtr = newPtr;
}

i) Is this logic correct?

ii) a) I possibly get a run-time error, when I insert two nodes (in one system) or three nodes(in another).
b) The nodes are inserted in the correct order, every time I insert a node.

Is the run-time error as a result of this code…???

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  1. Editorial Team
    Editorial Team
    2026-05-30T15:28:45+00:00Added an answer on May 30, 2026 at 3:28 pm
    struct node
    {
        int data; //or any type.
        struct node *nextPtr;
    }*start = NULL;
    //main
    struct *newPtr = (struct node *)malloc(sizeof(struct node));// You dont need * here
    
    scanf("%d", newPtr->data); //or cout
    newPtr->nextPtr = NULL;
    
    if(start == NULL)
        start = newPtr;
    else
    { 
        tempPtr = start; // you missed this.
        while(tempPtr->nextPtr != NULL)
        {
            tempPtr = tempPtr->nextPtr;
        }
        tempPtr->nextPtr = newPtr;
    }
    
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