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Home/ Questions/Q 283133
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:20:51+00:00 2026-05-12T05:20:51+00:00

I did batch to run SQL query like use [AxDWH_Central_Reporting] GO EXEC sp_spaceused @updateusage

  • 0

I did batch to run SQL query like

use [AxDWH_Central_Reporting]
GO
EXEC sp_spaceused @updateusage = N'TRUE'
GO

It displays 2 tables and generates some ugly report with some kind of ‘P’ unneeded letters… See below

Changed database context to 'AxDWH_Central_Reporting'.

database_name                                                                                                                   Pdatabase_size     Punallocated space 
--------------------------------------------------------------------------------------------------------------------------------P------------------P------------------
AxDWH_Central_Reporting                                                                                                         P10485.69 MB       P7436.85 MB        
reserved          Pdata              Pindex_size        Punused            
------------------P------------------P------------------P------------------
3121176 KB        P3111728 KB        P7744 KB           P1704 KB           
----------------------------------------------------------------

I also tryed to generate 1 table from this procedure with next query

declare
    @dbname sysname,
    @dbsize bigint,
    @logsize bigint,
    @reservedpages  bigint

select
    @reservedpages = sum(a.total_pages)
from
    sys.partitions p join sys.allocation_units a on p.partition_id = a.container_id left join sys.internal_tables it on p.object_id = it.object_id

select
    @dbsize = sum(convert(bigint,case when status & 64 = 0 then size else 0 end)),
    @logsize = sum(convert(bigint,case when status & 64 <> 0 then size else 0 end))

from 
    dbo.sysfiles

select 
    'database name' = db_name(),
    'database size' = ltrim(str((convert (dec (15,2),@dbsize) + convert (dec (15,2),@logsize)) * 8192 / 1048576,15,2) + ' MB'),
    'unallocated space' = ltrim(str((case when @dbsize >= @reservedpages then
        (convert (dec (15,2),@dbsize) - convert (dec (15,2),@reservedpages)) * 8192 / 1048576 else 0 end),15,2) + ' MB')

But got similar ugly report:

database name                                                                                                                   Pdatabase size     Punallocated space 
--------------------------------------------------------------------------------------------------------------------------------P------------------P------------------
master                                                                                                                          P5.75 MB           P1.52 MB           

(1 rows affected)

Is it possible to change the layout formatting for report? To make it more beautifull?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:20:51+00:00Added an answer on May 12, 2026 at 5:20 am

    I doubt you can get SQLCMD and sp_spaceused formatted nicely – why don’t you just use some other means of getting the information you need?

    In SQL Server 2005 and up, use this piece of T-SQL to display the tables and the size they use:

    SELECT 
        t.NAME AS TableName,
        i.name as indexName,
        p.[Rows],
        sum(a.total_pages) as TotalPages, 
        sum(a.used_pages) as UsedPages, 
        sum(a.data_pages) as DataPages,
        (sum(a.total_pages) * 8) / 1024 as TotalSpaceMB, 
        (sum(a.used_pages) * 8) / 1024 as UsedSpaceMB, 
        (sum(a.data_pages) * 8) / 1024 as DataSpaceMB
    FROM 
        sys.tables t
    INNER JOIN      
        sys.indexes i ON t.OBJECT_ID = i.object_id
    INNER JOIN 
        sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
    INNER JOIN 
        sys.allocation_units a ON p.partition_id = a.container_id
    WHERE 
        t.NAME NOT LIKE 'dt%' AND
        i.OBJECT_ID > 255 AND   
        i.index_id <= 1
    GROUP BY 
        t.NAME, i.object_id, i.index_id, i.name, p.[Rows]
    ORDER BY 
        object_name(i.object_id) 
    

    Works just fine for me! 🙂

    Marc

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