Question

I did the XSLT transformation.

What I missing is nil attribute. I mean that if source element has nil element true
I want to map it to destination XML.

<xsl:if 
test="string-length(soapenv:Envelope/soapenv:Body/b:getBLResponse/b:result/BResult:BLOut/Class:ID)=0">
    <xsl:attribute name="i:nil">true</xsl:attribute>
</xsl:if>

The if above working for specific node , but I want to make it as general template,
not to check every field

May be it is possible to create template which will receive xml node, than will be validation if node has nil attribute if it is , it will return with the nil attribute
otherwise without nil attribute.

Below is example

With nil: Input:

<TEST>
    <Child i:nil="true">asdf</Child>
</TEST>
Output:

<TEST xmlns:i="whatever" >
    <OutputChild i:nil="true">asdf</OutputChild >
</TEST>

Without nil: Input + Output the same

<TEST>
    <OutputChild >example</OutputChild >
</TEST>

Answer 1

In order to solve it , I wrote the template, which receives mapping node, and new element name. After checking if element is null, the template return nil attribute

<xsl:template name="TransformNode" >
        <xsl:param name="pCurrentNode"/>
        <xsl:param name="elementName"/>
        <xsl:element name = "{$elementName}">
            <xsl:if test="$pCurrentNode/@i:nil='true'"><xsl:attribute name="nil">true</xsl:attribute></xsl:if>      
            <xsl:value-of select="$pCurrentNode"/>
        </xsl:element>
    </xsl:template>