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Home/ Questions/Q 6547909
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:53:16+00:00 2026-05-25T11:53:16+00:00

I do have a string like the following 1 1/2 + 2 2/3 Now

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I do have a string like the following
“1 1/2 + 2 2/3”

Now i want the “1 1/2” as a variable, and the “2 2/3” as a different variable.
How do i fix this?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:53:16+00:00Added an answer on May 25, 2026 at 11:53 am

    If you are always going to have a ‘+’ inbetween, you could simply do:

    var splitStrings = stringWithPlus.Split('+');
    for (int i = 0; i < splitStrings.Length; i++) {
       splitStrings[i] = splitStrings[i].Trim();
    }
    

    edit: If you really wanted to put these two parts into two separate variables, you could do so. But it’s quite unnecessary. The type of the var is going to be string[] but to get them into two variables:

    var splitStrings = stringWithPlus.Split('+');
    for (int i = 0; i < splitStrings.Length; i++) {
       splitStrings[i] = splitStrings[i].Trim();
    }
    string firstHalf = splitStrings[0];
    string secondHalf = splitStrings[1];
    

    It would be better though, to just access these strings via the array, as then you’re not allocating any more memory for the same data.

    If you are comfortable with Linq and want to shorten this (the above example illustrates exactly what happens) you can do the split & foreach in one line:

    var splitStrings = stringWithPlus.Split('+').Select(aString => aString.Trim()).ToArray();
    string firstHalf=splitStrings[0];
    string secondHalf=splitStrings[1];
    

    If this syntax is confusing, you should do some searches on Linq, and more specifically Linq to Objects.

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