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Home/ Questions/Q 8673175
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T19:23:29+00:00 2026-06-12T19:23:29+00:00

I do not want use each and every time parseInt(’08’, 10) for each string

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I do not want use each and every time parseInt('08', 10) for each string to integer conversion,

Can we modify parseInt method, so that i can use only parseInt('08') instead of parseInt('08', 10).?

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  1. Editorial Team
    Editorial Team
    2026-06-12T19:23:31+00:00Added an answer on June 12, 2026 at 7:23 pm

    Instead of modifying the built-in function parseInt, you can define your own function like this:

    function prseInt(n)
    {
        return parseInt(n, 10);
    }
    

    And replace all the occurences of parseInt(n, 10) you have used in your app with prseInt(n).

    Fine, if you still wanna redefine, you can do this:

    var origParseInt = parseInt;
    parseInt = function(n) {
         return origParseInt(n, 10);
    }
    

    And it works!

    Fiddle: http://jsfiddle.net/QKKwv/

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