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Home/ Questions/Q 6532385
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T09:59:43+00:00 2026-05-25T09:59:43+00:00

I don’t know if this is really rereduce but that’s why I’m here. I

  • 0

I don’t know if this is really rereduce but that’s why I’m here.

I have this:

“afrikan” ID: f6733302df85ac109397f4b6030005bf [1, 2]

“afrikan” ID: f6733302df85ac109397f4b6030006d1 [1, 3]

“afrikan” ID: f6733302df85ac109397f4b6030012b6 [2, 4]

“chinese” ID: f6733302df85ac109397f4b6030012eb 1

“chinese” ID: f6733302df85ac109397f4b603001d87 1

I know how to calculate the sum if the value wasn’t an array (like in
chinese). But I can’t manage to sum the values in the array and it
results in this: “afrikan” “02,41,31,2”

And one more question: is there a way to sum all the values regardless
of keys?

View code:

function(doc) {
  if(doc.food) {
  emit(doc.food, doc.type);
  }
}

Reduce code:

function(keys,values,rereduce) 
{

return sum(values);

}

Thank you a lot 🙂

UPDATE:

I found an answer for Couchdb.

Here is the code:

function(doc) {
if(doc.food) {
if(doc.type.length>1) {
 doc.type.forEach(function(tag) {
emit(doc.food,tag);
});
}else {
emit(doc.food,doc.type);
}
}
}

Reduce:

function(keys,values) {
return sum(values);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T09:59:43+00:00Added an answer on May 25, 2026 at 9:59 am

    The reason you get “02,41,31,2” is because Javascript will convert a number + an array into a string. It is very strange, but true.

    > 0 + [2, 4] + [1, 3] + [1, 2]
    '02,41,31,2'
    
    > sum([0, [2, 4], [1, 3], [1, 2]]) // Same result
    '02,41,31,2'
    

    I think you do not need to worry about rereduce. Just add every value together. If it is an array, add all the values in the array.

    function(keys, values, rereduce)
    {
      var total = 0;
      var i, j;
    
      for(i = 0; i < values.length; i++) {
        if(typeof values[i] == "number") {
          total = total + values[i];
        }
    
        else {
          for(j = 0; j < values[i].length; j++) {
            total = total + values[i][j];
          }
        }
      }
    }
    
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