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Home/ Questions/Q 7042125
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Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T02:07:49+00:00 2026-05-28T02:07:49+00:00

I don’t know PHP. I don’t want the user to go to http://www.example.com/feedback-thanks.html after

  • 0

I don’t know PHP.

I don’t want the user to go to http://www.example.com/feedback-thanks.html after sending the form. What I want is text below the sent button or anything without refreshing the page.

I removed header( "Location: http://www.example.com/feedback-thanks.html" ); but i don’t receive the e-mail and the user is redirected to feedback.php… 🙁

html

<form method="post" action="feedback.php">
<input name="email" type="email"/>
<textarea name="message" id="feedback-textarea" autofocus="autofocus" required="required" ></textarea>
<button type="submit" id="feedback-button-send">send</button>
</form>

feedback.php

<?php
  $email = $_REQUEST['email'] ;
  $message = $_REQUEST['message'] ;

  mail( "abcde@gmail.com", "Subject Here",
    $message, "From: $email" );
  header( "Location: http://www.example.com/feedback-thanks.html" );
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T02:07:50+00:00Added an answer on May 28, 2026 at 2:07 am

    You will have to use $.ajax() for that

    • http://net.tutsplus.com/tutorials/javascript-ajax/5-ways-to-make-ajax-calls-with-jquery/
    • http://www.sitepoint.com/ajax-jquery/

    this is what I use in one of my apps

    $('#submitSearch').click(function() {
    
            var formData = {
                searchData: $('#searchData').val(),
            };
    
            $.ajax({
                url: siteUrl + 'fetch/search',
                type: "POST",
                data: formData,
                cache: true,            
                beforeSend:function(){
                    jQuery('#main').html('<div class="loading"><img src="' + siteUrl + 'resources/imgs/ajax-loader.gif" alt="Loading..." /></div>');
                },
                success: function(data) {
                    jQuery('#main').empty();
                    jQuery('#main').append(data);
                },
                error:function(x,e){
                    if(x.status==0){
                        alert('You are offline!!\n Please Check Your Network.');
                    }else if(x.status==404){
                        alert('Requested URL not found.');
                    }else if(x.status==500){
                        alert('Internel Server Error.');
                    }else if(e=='parsererror'){
                        alert('Error.\nParsing JSON Request failed.');
                    }else if(e=='timeout'){
                        alert('Request Time out.');
                    }else {
                        alert('Unknow Error.\n'+x.responseText);
                    }
                }
            });
            return false;
        });
    
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