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Home/ Questions/Q 6986693
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:50:31+00:00 2026-05-27T18:50:31+00:00

I don’t know what I’m doing wrong, but my little update code is giving

  • 0

I don’t know what I’m doing wrong, but my little update code is giving me an error message that I can’t work out how to resolve it.

Here’s my code:

<?php

     include('dbconfig.php');
     $con = mysql_connect($host, $username, $password) or die(mysql_error()) ; 

     if (!$con){
         die('Could not connect: ' . mysql_error());
      }
        mysql_select_db($db, $con);

       function sqlEscape($string){     
          return "'".mysql_real_escape_string($string)."'";
       }

        if(isset($_POST['submit'])){


    $q  =  "UPDATE records SET `name` = " + sqlEscape($_POST['name']) + ", 
    `age` = " + sqlEscape($_POST['age']) + ", 
    `location` = " + sqlEscape($_POST['location']) + ", 
    `telephone` = " + sqlEscape($_POST['telephone']) + "

     WHERE id = $_POST[id]";                

     mysql_query($q) or die(mysql_error());

     }                  
  ?>

Here’s the error message it prints out:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '0' at line 1

Can someone see where I’m going wrong at all?

Thanks for your help.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:50:32+00:00Added an answer on May 27, 2026 at 6:50 pm
    $q  =  "UPDATE records SET `name` = " . sqlEscape($_POST['name']) . ", 
        `age` = " . sqlEscape($_POST['age']) . ", 
        `location` = " . sqlEscape($_POST['location']) . ", 
        `telephone` = " . sqlEscape($_POST['telephone']) . "
    
         WHERE id = $_POST[id]";
    

    Use “.” instead of “+” to concat strings in PHP.

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