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Home/ Questions/Q 730327
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:53:57+00:00 2026-05-14T06:53:57+00:00

I don’t know why I’m having so much trouble groking the documentation for the

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I don’t know why I’m having so much trouble groking the documentation for the elisp debugger.

I see it has a commands to “step-into” (d). But for the life of me, I cannot see a step-out or step-over.

Can anyone help?

If I have this in the Backtrace buffer:

Debugger entered--returning value: 5047
  line-beginning-position()
* c-parse-state()
* byte-code("...")
* c-guess-basic-syntax()
  c-show-syntactic-information(nil)
  call-interactively(c-show-syntactic-information)

…where do I put the cursor, and what key do I type, to step out of the parse-state() fn ? by that I mean, run until that fn returns, and then stop in the debugger again.

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:53:57+00:00Added an answer on May 14, 2026 at 6:53 am

    ‘c’ and ‘j’ work kind of like a step-out and step-over. When a flagged frame (indicated by “*”) is encountered (the docs say “exited” but this doesn’t seem to be how the debugger behaves), the debugger will be re-entered. When the top frame is flagged, they work like step-over; when it isn’t, they work like step-out.

    In your example backtrace, typing either will step out of line-beginning-position into c-parse-state. The frame flag should clear, so typing either a second time should step out of c-parse-state.

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