I don’t quite understand the \ and \.. syntax in the compile error I’m getting
Error 6 The command ” copy
c:\project\new\..
\new\bin\x64\debug\garmin.dll
c:\project\new\bin\x64\Debug\ ”
exited with a code 1.
Can anyone explain this to me?
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\..\simply means “the parent directory”. So in this case,\new\..\new\contains redundancy, and simply means\new\. You are trying to copy a file to the directory it is already in, but it won’t happen because the file already exists (and perhaps is in use?)