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Home/ Questions/Q 7990699
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:05:29+00:00 2026-06-04T13:05:29+00:00

I don’t quite understand what’s wrong with my function that I wrote, When I

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I don’t quite understand what’s wrong with my function that I wrote,

When I pass an array to it, eg:

var pvars=['health/1/1.jpg','health/1/2.jpg','health/1/3.jpg','health/1/4.jpg'];
cache_threads(pvars,1);

Then I end up with an empty variable, eg:

alert(pvars);

Returns an empty string.

Here is my function:

var cache_threads=function (arruy,quant){
    if (quant==undefined) quant=1;
var div=Math.ceil(arruy.length/quant);
var a = arruy;
while(a.length) {
    cache_bunch(a.splice(0,div));
}
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:05:31+00:00Added an answer on June 4, 2026 at 1:05 pm

    a and arruy are the same array.

    When you .splice one, you’ll be splicing the other one, too!

    If you want a (shallow) copy of the array, use .slice():

    var a = arruy.slice(0);
    
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