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Home/ Questions/Q 8664595
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T17:16:42+00:00 2026-06-12T17:16:42+00:00

I don’t think I am passing the variable the right way between my separate

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I don’t think I am passing the variable the right way between my separate PHP and AJAX files.

I am debugging this by triggering the second condition $status = 'info'; in my PHP file.

Currently, status is coming up as “undefined” for alert(data.status);

signup_process.php

if (condition){

   $status = 'success';

else {

    $status = 'info';

    }

AJAX

function send() {
var data = $('#signup_form').serialize();
    $.ajax({
        type: "POST",
        url: "signup_process.php",
        data: data,
        success: function (data) {
        alert(data.status);
            if (data.status == 'success') {
                // everything went alright, submit
                $('#signup_form').submit();
            } else if (data.status == 'info')
            {
                console.log(data.status);
                $("label#email_error").show(); 
                return false; 
            }
        }
    });
    return false;
};

I know that the 2nd condition is being triggered because I put a header redirect there just for testing and it worked fine.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T17:16:43+00:00Added an answer on June 12, 2026 at 5:16 pm

    Good to use json while return back data from php to ajax.

    $return_data = array();
    if (condition){
       $return_data['status'] = 'success';
    } else {
        $return_data['status'] = 'info';
    }
    
    echo json_encode($return_data);
    exit();
    

    Now, if you are return back json data to ajax, then you need to specify return data type into ajax call as below

    function send() {
    var data = $('#signup_form').serialize();
        $.ajax({
            type: "POST",
            url: "signup_process.php",
            data: data,
            dataType: 'json', 
            success: function (data) {
            alert(data.status);
                if (data.status == 'success') {
                    // everything went alright, submit
                    $('#signup_form').submit();
                } else if (data.status == 'info')
                {
                    console.log(data.status);
                    $("label#email_error").show(); 
                    return false; 
                }
            }
        });
        return false;
    };
    
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