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Home/ Questions/Q 5994535
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T23:49:54+00:00 2026-05-22T23:49:54+00:00

I don’t understand function closures and anonymous functions very well. What I’m trying to

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I don’t understand function closures and anonymous functions very well. What I’m trying to do is create a function that runs the inputted function randomly based on a dice roll:

repeat(1,6,foobar());

function repeat(numDie, dieType, func){
    var total = 0;
    for (var i=0; i < numDie; i++){
        var dieRoll = Math.floor(Math.random()*dieType)+1;
        total += dieRoll;
    }
    for (var x=0; x < total; x++){
        func();
    }
}

What exactly am I doing wrong here? Do I have to store the function in a variable to use it?

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  1. Editorial Team
    Editorial Team
    2026-05-22T23:49:54+00:00Added an answer on May 22, 2026 at 11:49 pm

    By writing foobar(), you’re calling foobar and passing its return value.

    Remove the parentheses to pass the function instead of calling it.

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