Question

i don’t understand how this happen. This is portion of my code..

   int isGoal(Node *node, int startNode){

       int i;
   .
   .
   }

When i debug this using gdb i found out that ‘i’ was allocated at the memory address that have been previously allocated.

(gdb)print &node->path->next
$26 = (struct intNode **) 0xffbff2f0

(gdb) print &i
$22 = (int *) 0xffbff2f0

node->path->next has been already defined outside this function. But as u can see they share the same address which at some point make the pointer point to another place when the i counter is changed.

I compiled it using gcc on solaris platform
Any helps would be really appreciated..

Answer 1

Two possibilities:

• You have compiled with optimizations and this is confusing gdb (for example i could be optimized away, so that it actually hasn’t any address)
• node->path doesn’t point to correctly allocated memory. For example that pointer could have been set to point to an object on the stack that subsequently went out of scope.