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Home/ Questions/Q 6910353
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:48:13+00:00 2026-05-27T08:48:13+00:00

I don’t understand what is wrong with this code. Sometimes two threads start executing

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I don’t understand what is wrong with this code. Sometimes two threads start executing the try block. I am creating a new instance of popo every time I call the function. Can please anybody figure out what the problem is?

public class Instance {
  private static AtomicInteger i = new AtomicInteger(0);

  public synchronized void incrementInstance() {
    i.getAndIncrement();
  }

  public synchronized void decrementInstance() {
    i.getAndDecrement();
  }

  public synchronized int getInstances() {
    return i.get();
  }
}

public class popo {
  private static volatile MyMutex instanceMutex = new MyMutex();

  public void doSomething() {
    synchronized (instanceMutex) {
      final Instance no = new Instance();
      if (no.getInstances() > 0) {
         instanceMutex.wait();
      } else {
         no.incrementInstance();
      }
    }

    try {
     // do something
    } finally {
        synchronized (instanceMutex) {
          final Instance no = new Instance();
          if (no.Instances() > 0) {
            no.decrementInstance();
          }
          instanceMutex.notify();
        }
     }
  }
  private static class MyMutex {}
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:48:14+00:00Added an answer on May 27, 2026 at 8:48 am

    I think the code smells all over the place 🙂 Actually, doing things like creating new instances that do nothing more than access a static field make things confusing (see previous responses). So, this is what I suggest:

    1. You should avoid using wait/notify if you are writing new code. Take a look to the concurrent package and to the Item69 in the Effective Java book.
    2. Based on what I understand from your code, you need a Semaphore like:
    static final Semaphore SEMAPHORE = new Semaphore(1);
    ...
    
    SEMAPHORE.take(); // blocks, only one thread is allowed to proceed
    
    try{
       //critical section
    } finally {
        SEMAPHORE.release(); // never blocks, always within a finally block
    }
    

    Then you can use the method getQueueLength() to know how many threads are waiting and replace the AtomicInteger you are using. See http://docs.oracle.com/javase/6/docs/api/java/util/concurrent/Semaphore.html

    1. Consider using an executor. Then, once you submit the task, you can wait for the Future.
    2. If you still want to use wait/notify, make sure to put all the code within the synchronized block and to use the standard idiom (Item69 from Effective Java):
    synchronized(instanceMutex) {
        while(< condition does not hold >) {
            obj.wait();
        }
    
        // Perform required actions
    }
    
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