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Asked: 2026-06-10T15:59:36+00:00

I don’t unserstand why PHP doesn’t make replacements in strings containing dollar signs. Look

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I don’t unserstand why PHP doesn’t make replacements in strings containing dollar signs.
Look at the following example:

<?php
error_reporting (E_ERROR | E_WARNING | E_PARSE | E_NOTICE);
$var = 1024;
$str = '$var';
echo $str, '<br>', "$str";

Output is $var $var. Why is it so? Everything is clear with first echo parameter, but I expected that the last parameter will give a different result (1024), because it contains dollar sign encapsulated by double quotes, so it should be interpreted as variable and replaced to 1024. Where am I going wrong?

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1 Answer

  1. Editorial Team

    $str contains a string with the content of "$var" (no variable replacement, just these very characters). It was created using single quotes, so no variable replacement there.

    When echoing it using echo "$str", the variable $str gets replaced with its content, namely the string "$var", thus resulting in your output.

    The string replacement in double quotes strings does not work recursively! So in order to have $str replaced by 1024 in the second appearance, you have to create $str using double quotes in the first place.

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