Question

I executed the following code:

import sys

x=sys.argv[1]

print x;

if x > 1:
    print "It's greater than 1"

and here is the output:

C:\Python27>python abc.py 0
0
It's greater than 1

How the hell it’s greater than 1? in fact the if condition should fail, is there any fault with my code?

Answer 1

Because type of x in x=sys.argv[1] is str.

import sys
x = sys.argv[1]
print type(x)

Output =<type 'str'>

So in python,

>>> '0'>1
True

Therefore you need

>>> int('0')>1
False
>>>