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Editorial Team
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Asked: 2026-05-15T03:20:25+00:00

I expected the code below to alert 0 and 1, but it alert 2

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I expected the code below to alert “0” and “1”, but it alert “2” twice. I don’t understand the reason. Don’t know if it is a problem of jQuery. Also, please help me to edit title and tags of this post if they are inaccurate.

<html>
    <head>
        <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
        <script type="text/javascript">
            $(function() {
                for (var i=0; i<2; i++) {
                    $.get('http://www.google.com/', function() {
                        alert(i);
                    });
                }
            });
        </script>
    </head>
    <body>
    </body>
</html>
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1 Answer

  1. Editorial Team

    You’re sharing the single i variable among all of the callbacks.

    Because Javascript closures capture variables by reference, the callbacks will always use the current value of i. Therefore, when jQuery calls the callbacks after the loop executes, i will always be 2.

    You need to reference i as the parameter to a separate function.

    For example:

    function sendRequest(i) {
    $.get('http://www.google.com/', function() {
        alert(i);
    });
}

for (var i = 0; i < 2; i++) {
    sendRequest(i);
}

    This way, each callback will have a separate closure with a separate i parameter.

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