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Home/ Questions/Q 8675731
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T20:01:06+00:00 2026-06-12T20:01:06+00:00

I expected the first example code produces the result same as the second one

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I expected the first example code produces the result same as the second one but it didn’t. So in order to get the correct class name, I have to redefine the custom msg() method in the extended class.

I’d like to know why the first one does not produce the extended class name and why it does when the method is redefined which is exactly the same.

Example 1

call_user_func(array(new MyClass_Mod, "msg"));

class MyClass {
    function msg() {
        echo '<p>get_class(): ' . get_class() . '</p>';
    }
}
class MyClass_Mod extends MyClass {
}

output

get_class(): MyClass

Example 2

call_user_func(array(new MyClass_Mod, "msg"));

class MyClass {
    function msg() {
        echo '<p>get_class(): ' . get_class() . '</p>';
    }
}
class MyClass_Mod extends MyClass {
    function msg() {
        echo '<p>get_class(): ' . get_class() . '</p>';
    }
}

output

get_class(): MyClass_Mod

I’d like to know the mechanism, so please do not suggest to use get_called_class(). I’m not able to use it for the version below PHP 5.3. Thanks for your input.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T20:01:07+00:00Added an answer on June 12, 2026 at 8:01 pm

    You just have to pass $this argument to get_class function.

    get_class($this);
    
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