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Home/ Questions/Q 6723121
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:31:50+00:00 2026-05-26T09:31:50+00:00

I fail to understand the hex annotation at the MSDN site On the following

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I fail to understand the hex annotation at the MSDN site

On the following MSDN site: DDS file spec

there is a table at dwFlags. dwFlags is a DWORD (4 Bytes or 0x00000000)

Question: The hex annotations for a value (e.g.) 0x800000 are confusing me, which bit (of the 32) do I have to flip?

Please ‘translate’ the value coloumn of the source (just 8 values)

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:31:51+00:00Added an answer on May 26, 2026 at 9:31 am

    0x800000 is the same as 100000000000000000000000 in binary.

     1000 0000 0000 0000 0000 0000
     ^  ^    ...       ^    ^    ^
    23 20    ...       8    4    0   = bit position
    

    So it’s the 23rd bit.

    For dwFlags does this mean:

    0x1      = 1
    0x2      = 10
    0x4      = 100
    0x8      = 1000
    0x1000   = 1000000000000
    0x20000  = 100000000000000000
    0x80000  = 10000000000000000000
    0x800000 = 100000000000000000000000
    
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