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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T23:53:39+00:00 2026-05-17T23:53:39+00:00

I feel as though there should be a simple way to do this, but

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I feel as though there should be a simple way to do this, but searching around gives me no good leads. I just want to open() a pipe to an application, write some data to it, and have the output of the subprocess sent to the STDOUT of the calling script.

open(my $foo, '|-', '/path/to/foo');
print $foo 'input'; # Should behave equivalently to "print 'output'"
close($foo);

Is there a simple way to do this, or have I hit upon one of the many “can’t get there from here” moments in Perl?

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  1. Editorial Team
    Editorial Team
    2026-05-17T23:53:40+00:00Added an answer on May 17, 2026 at 11:53 pm

    The subprocess will inherit STDOUT automatically. This works for me:

    open(my $f, "|-", "cat");
    print $f "hi\n";
    

    If you are not really closing the pipe immediately the problem might be on the other end: STDOUT is line-buffered by default, so you see print "hello world\n" immediately. The pipe to your subprocess will be block-buffered by default, so you may actually be waiting for the data from your perl script to reach the other program:

    open(my $f, "|-", "cat");
    print $f "hi\n";
    sleep(10);
    close($f); # or exit
    # now output appears
    

    Try adding select $f; $| = 1 (or I think the more modern way is $f->autoflush(1))

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