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Home/ Questions/Q 6029037
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T04:49:38+00:00 2026-05-23T04:49:38+00:00

I feel like a real noob asking this, but here’s my problem: I want

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I feel like a real noob asking this, but here’s my problem:

I want to show a tableView, with 7 custom cells. None of these cells is reused. That means the user will see 7 different cells, not more, not less.

I created the cells in the viewDidLoad method, and added all those cells in the listCells-array. After that, I used easy-mode to draw those cells:

UITableViewCell *cell = nil;
if (indexPath.row == 0)
{
    static NSString *MyIdentifier = @"Cell";
    cell =  (DetAlertCell *)[localTableView dequeueReusableCellWithIdentifier:nil];

    if (cell == nil) {
        [[NSBundle mainBundle] loadNibNamed:@"DetAlertCell" owner:self options:nil];
        cell = [listCells objectAtIndex:indexPath.row];
    }
}
....

However, this won’t work. It shows me a blank view. Every cell is created using a .xib-file and a .h and .m class. Is there anything that I’m missing and should do?

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  1. Editorial Team
    Editorial Team
    2026-05-23T04:49:39+00:00Added an answer on May 23, 2026 at 4:49 am

    Just don’t call the [localTableView dequeueReusableCellWithIdentifier:nil] and loa the correct cell for the index path.

    Also you say that you load the cells in the viewDidLoad, then why do you load the nib:

     [[NSBundle mainBundle] loadNibNamed:@"DetAlertCell" owner:self options:nil];
    

    They should already be the array should they not.
    And why to you check if the row is 0 then load the row, still will only load the first row.

    Try this:

    - (UITableViewCell *) tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
       return [listCells objectAtIndex:indexPath.row];
    }
    
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