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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T07:46:15+00:00 2026-06-12T07:46:15+00:00

I feel like this must be very easy, but I can’t find the answer

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I feel like this must be very easy, but I can’t find the answer anywhere. In octave (and probably matlab but I haven’t verified), you can source the contents of a file by doing


source /path/to/filename

However, let’s say I have the filename stored in a variable called file. If you do source file, it treats file as the path rather than what is stored in file. I have tried inserting eval in various places but if that is the answer, I haven’t found the correct invocation. I don’t know much octave; there is surely a trivial answer to this that I am overlooking?

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  1. Editorial Team
    Editorial Team
    2026-06-12T07:46:16+00:00Added an answer on June 12, 2026 at 7:46 am

    Not sure about octave, but try to use a function call

    source(fname)
    

    That’s what you do in matlab at least.

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