Question

I find database records which are duplicated like so :

select s.name, r.name Region, c.name Country
from supplier s
join region r on r.id = s.regionid
join region c on c.id = isnull(r.pid, r.id)
group by s.name, r.name, c.name
having count(s.name) >1 

whats the best way to list them all (so if two duplicates it will appear twice etc…)

Answer 1

The easiest way is to create an in-line query from your Find-dups query and join to a “without-a-group-by” query.

select s.name, r.name Region, c.name Country
     from supplier s
     join region r on r.id = s.regionid
     join region c on c.id = isnull(r.pid, r.id)
     inner join (select s.name, r.name Region, c.name Country
                from supplier s
                join region r on r.id = s.regionid
                join region c on c.id = isnull(r.pid, r.id)
                group by s.name, r.name, c.name
                having count(s.name) >1 ) dups
     ON s.name = dups.name
        and r.name = dups.region
        and c.name = dups.country