Question

I find myself often needing to use Integer.TryParse to test if a value is an integer. However, when you use TryParse, you have to pass a reference variable to the function, so I find myself always needing to create a blank integer to pass in. Usually it looks something like:

Dim tempInt as Integer If Integer.TryParse(myInt, tempInt) Then 

I find this to be quite cumbersome considering that all I want is a simple True / False response. Is there a better way to approach this? Why isn’t there an overloaded function where I can just pass the value I want to test and get a true / false response?

Answer 1

No need to declare the integer.

If Integer.TryParse(intToCheck, 0) Then 

or

If Integer.TryParse(intToCheck, Nothing) Then 

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If you have .Net 3.5 ability you can create an extension method for strings.

Public Module MyExtensions      <System.Runtime.CompilerServices.Extension()> _     Public Function IsInteger(ByVal value As String) As Boolean         If String.IsNullOrEmpty(value) Then             Return False         Else             Return Integer.TryParse(value, Nothing)         End If     End Function  End Module 

And then call like:

If value.IsInteger() Then 

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Sorry, getting carried away I know, but also you can add this to the MyExtensions class above in .Net 3.5 and not worry unless you need validations.

<System.Runtime.CompilerServices.Extension()> _ Public Function ToInteger(ByVal value As String) As Integer     If value.IsInteger() Then         Return Integer.Parse(value)     Else         Return 0     End If End Function 

Then simply use

value.ToInteger() 

This will return 0 if it isn’t a valid Integer.