Question

I find myself using jQuery objects with regular js objects often; I’m trying to figure out how I can utilize .call and .apply more often in my scripts when appropriate. I’ve been testing code to see how it actually works.

However when I run my code below (which essentially just hides all the divs on the page) in firebug on sites I know have jQuery I get varied results; I’m wondering if it’s the version of jQuery or is this code just ‘buggy’ I am to decipher why .call always works but .apply doesn’t thought it would be the other way around based on code below

var myApp = {} // instantiate an empty objct
myApp.hide = function (whatever) {
   that = whatever
   $(that).hide()
}
var Numbers = function (object) {
this.object = object;
}

Numbers.prototype.div = $('div');
var numbers = new Numbers();
numbers.div
myApp.hide.call(numbers, numbers.div)
myApp.hide.apply(numbers, numbers.div)

When I firebug the code above either using .call or .apply I get different result depending upon the site. Every site that has jquery .call will work but for some sites like jQuery.com and twitter both will work using .apply and .call but other sites like New York Times and Netflix only .call works – I’m guessing it’s the version of jQuery that’s causing the difference but am slightly confused because numbers.div always returns an array of all div elements on the page so I would think that would work all the time. Any explanation is appreciated as I am still grasping the concepts of .call and .apply – I always reference Douglas Crockford’s book but truthfully he doesn’t go into much detail about .apply and .call

Answer 1

.apply need you to pass the arguments as an array.

SO

myApp.hide.call(numbers, numbers.div)

should be same as

myApp.hide.apply(numbers, [numbers.div])

But, in your myApp.hide function, there is no this, so the first parameter of .call or .apply can be anything else, it doesn’t matter.